PHP Program to Find Year is Leap OR Not



In this post I am going to describe the basic PHP Program which tell us weather the year is Leap or not. Leap year are year which has one extra day and the year which are completely divisible by 4 are leap Year. We will use same logic in the program.


<html>
	<head>
		<title>Leap Year</title>
	</head>
	<body>
		<form action="" method='POST'>
		<label for="number">Please Enter a Year</label>
		<input type="text" name="number" value="">
		<br><br>
		
		<input type="submit" value="Done" name="submit">
		</form>
	</body>
</html>

<?php
if(isset($_POST['submit'])){
	$number= $_POST['number'];
	if($number%4==0)
	{
		echo "Year is Leap Year";
	}
	else{
		echo "Year is not Leap Year";
	}
}
?>

Program Output:

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